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Chapter 2 Practice Test 151

Chapter 2 Practice Test EXTRA PREPARED TEST
You can find an additional test for
Chapter 2 by clicking on the link in the
Section I: Multiple Choice Select the best answer for each question. TE-book or by logging into the teachers’
1. Many professional schools require applicants to take resources on our digital platform. Practice Test
a standardized test. Suppose that 1000 students take
such a test. Several weeks after the test, Pete receives
his score report: he got a 63, which placed him at the
73rd percentile. This means that: FULL SOLUTIONS TO CHAPTER 2

(a) Pete did worse than about 63% of the test takers. PRACTICE TEST

(b) Pete did worse than about 73% of the test takers.

(c) Pete did better than about 63% of the test takers. You can find the full solutions to the

(d) Pete did better than about 73% of the test takers. Chapter 2 Practice Test by clicking on the
1.21.05(C) 2021 BFW Publishers -- for review purposes only.

2. The density curve shown models the distribution of a link in the TE-book or by logging into
quantitative variable that is equally likely to take any the teachers’ resources on our digital
value in the interval from 0 to 2. What percent of the –8 –6 –4 –2 0 2 4 6 8 10 12
observations lie between 0.5 and 1.2? platform.
5. Scores on the ACT college entrance exam can be mod-

0.5 eled using a normal distribution with mean 21 and
standard deviation 5. Wayne’s standardized score on Answers to Chapter 2
the ACT was 0.6− . What was Wayne’s actual ACT
score? Practice Test
(a) 3
0 1 2 (b) 13 1. d
25%
(a) (c) 16 2. b
(b) (d) 18 3. a
35%
(c) 6. The Environmental Protection Agency (EPA) requires
50%

70%
(d) that the exhaust from each model of motor vehicle 4. c
be tested for the level of several pollutants. The level

3. Which of the following is closest to the 28th percentile of oxides of nitrogen (NOX) in the exhaust of one 5. d
of the standard normal distribution? light truck model was found to vary among individual
(a) =−z 0.58 trucks according to an approximately normal distri- 6. a

(b) =−z 0.50 bution with mean µ = 1.50 grams per mile driven and

(c) z = 0.39 standard deviation σ = 0.25 gram per mile. Which of
the following best estimates the percent of light trucks
(d) z = 0.61 of this model with NOX levels greater than 2 grams

4. For the normal distribution shown at top right, the per mile?
standard deviation is closest to (a) 2.5%
(a) 1. (b) 5%
(b) 2. (c) 16%
(c) 3. (d) 32%
(d) 6.
(ii) invNorm(area: 0.99,mean: 694,
03_StarnesSPA4e_24432_ch02_088_153.indd 151 (b) Boundary: 1 fluid ounce 07/09/20 1:59 PM
=
SD:112) 954.55. A GRE Chemistry z = –2.58 gives an area to the left close to
test score of 955 would be at the 99th 0.005.
percentile of the distribution. 11.1
−
−
11.05 −2.58 =
7. (a) (i) z = =−0.63 and SD
0.08 SD = 0.0388 fluidounce
−
z = =1.88; the proportion of To ensure that at least 99% of the restaurant’s
0.08 burgers have between 1 and 1.2 ounces of
z-scores between z = –0.63 and z =1.88 ketchup on them, the machine’s standard
is 0.9699–0.26430.7056. deviation has to be reduced to 0.0388 fluid
=
(ii) Applet/normalcdf(lower:1,upper:1.2, ounce.
=
mean:1.05, SD:0.08) 0.7036. About
70.4% of the time, between 1 and 1.2
ounces of ketchup will be put on the
burger.
CHAPTER 2 • Practice Test 151
03_TysonTEspa4e_25177_ch02_088_153_4pp.indd 151 10/11/20 7:49 PM