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92     CHAPTER 2   •  Modeling One-Variable Quantitative Data

                                                                           Finding and Interpreting Standardized Scores ( z -Scores)
                        TEACHING TIP                                   A percentile is one way to describe an individual’s location in a distribution of quanti-
                                                                     tative data. Another way is to give the   standardized score ( z -score) for the individual’s



                Students are unlikely to have prior                  location.
                experience with z-scores and their
                interpretation. Work through a few                            DEFINITION  Standardized score ( z -score)
                examples with them. As you talk with
                students, alternate the terms z-score                  The  standardized score  (  z   -score ) for an individual value in a distribution tells us how
                                                                      many standard deviations from the mean the value falls, and in what direction. To find
                and standardized score to get them                    the standardized score ( z -score), compute
                accustomed to both.                                                          valuemean
                                                                                                −
                                                                                              z =
                                                                                           standarddeviation
                COMMON ERROR
                           (C) 2021 BFW Publishers -- for review purposes only.
                Make sure students include direction                     Values larger than the mean have positive  z -scores. Values smaller than the mean
                when interpreting z-scores. It is                    have negative  z -scores.
                important that students understand                       Let’s return to the data from Mr. Pryor’s first statistics test. The following dotplot
                that a z-score measures the number of                displays the data, with Jenny’s score marked in red. The table provides numerical


                                                                     summaries for these data.


                standard deviations in a direction from

                the mean. It is not good enough to say




                “standard deviations away from the                                65  70  75   80  85   90  95
                mean.” Students should always indicate                                        Score
                whether an individual’s value is above                           Summary Statistics
                or below the mean.                                               n  Mean  SD  Min  Q 1  Med  Q 3  Max
                                                                                 25  80  6.07  67  76  80  83.5  93

                        TEACHING TIP
                                                                        Where does Jenny’s 86 fall within the distribution? Her standardized score (  -score) is
                                                                                                                   z
                It can be helpful to make two dotplots                                 value mean  86 80
                                                                                           −
                                                                                                    −
                                                                                                        099
                like the ones shown here. The top                                  z    =  standard deviation  =  607  =.
                                                                                                    .
                number line should be scaled in the                   That is, Jenny’s test score is 0.99 standard deviation above the mean score of the class.
                original units and the bottom number
                line should be scaled in z-scores.
                Point out that the mean test score        EXAMPLE
                corresponds to a standardized score
                of 0, scores above average correspond        How well did Lionel do?
                to positive standardized scores, and         Finding and interpreting  z -scores
                below-average scores correspond to             PROBLEM:       Find the standardized score ( z -score) for Lionel, who earned a 67 on Mr. Pryor’s first test. Interpret
                negative standardized scores.              this value.
                                                              SOLUTION:
                   Mr. Pryor’s test scores                  67 80                                   z  =  valuemean
                                                                                                          −
                                                              −
                             d   d                               z =  =− 2.14                         standarddeviation
                          d  d  dd  d
                      d  dddd dddddddddd  dd  d              6.07
                    65  70  75  80  85  90  95              Lionel’s score is 2.14 standard deviations below the class mean of 80.       FOR PRACTICE     TRY EXERCISE 11.
                            Test scores
                   Mr. Pryor’s test scores
                             d   d
                          d  d  dd  d
                      d  dddd  dddddddddd  dd  d
                      –2  –1   0   1    2         03_StarnesSPA4e_24432_ch02_088_153.indd   92  SOLUTION:  The caiman’s standardized   07/09/20   1:53 PM
                                                                   Mass (kg)
                                                          Mass (kg)
                             z-scores                                                  score is
                                                            7.2      8.0
                                                           10.0     15.0                         z  =  15 −9.81 ≈1.32
                  AL TERNA TE  EX AMPLE                     6.0      7.9                             3.93
                How big are Spectacled Caimans?             8.1      6.0               This caiman’s mass is 1.32 standard deviations
                                                           17.5     11.0               greater than the mean caiman mass of 9.81 kg.
                Finding and interpreting z-scores
                                                            8.2     17.0
                PROBLEM:  The spectacled caiman is
                a crocodilian reptile that lives in Central   6.2    9.2
                and South America. Researchers recorded
                the mass (in kilograms) of 14 caimans.   Variable  n  Mean  StDev Minimum  Q1  Median  Q3  Maximum
                The data are shown below, along with   Mass  14  9.81  3.93   6.00   7.20   8.15   11.00  17.50
                a dotplot and summary statistics. Find
                the standardized score (z-score) for the   d d d  d  dd  d  d  d  d  dd
                                                           dd
                caiman that has a mass of 15 kg. Interpret   6  7  8  9101112131415161718
                this value in context.                         Mass (kg)
                92        CHAPTER 2   •   Modeling One-Variable Quantitative Data
          03_TysonTEspa4e_25177_ch02_088_153_4pp.indd   92                                                             10/11/20   7:42 PM
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